(4x+3)(2x^2-9x-5)=0

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Solution for (4x+3)(2x^2-9x-5)=0 equation:


Simplifying
(4x + 3)(2x2 + -9x + -5) = 0

Reorder the terms:
(3 + 4x)(2x2 + -9x + -5) = 0

Reorder the terms:
(3 + 4x)(-5 + -9x + 2x2) = 0

Multiply (3 + 4x) * (-5 + -9x + 2x2)
(3(-5 + -9x + 2x2) + 4x * (-5 + -9x + 2x2)) = 0
((-5 * 3 + -9x * 3 + 2x2 * 3) + 4x * (-5 + -9x + 2x2)) = 0
((-15 + -27x + 6x2) + 4x * (-5 + -9x + 2x2)) = 0
(-15 + -27x + 6x2 + (-5 * 4x + -9x * 4x + 2x2 * 4x)) = 0
(-15 + -27x + 6x2 + (-20x + -36x2 + 8x3)) = 0

Reorder the terms:
(-15 + -27x + -20x + 6x2 + -36x2 + 8x3) = 0

Combine like terms: -27x + -20x = -47x
(-15 + -47x + 6x2 + -36x2 + 8x3) = 0

Combine like terms: 6x2 + -36x2 = -30x2
(-15 + -47x + -30x2 + 8x3) = 0

Solving
-15 + -47x + -30x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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